Question

A particle is launched at an angle of 37° from horizontal. If the horizontal velocity component is 7.65 meters/second, what is the resultant velocity of the particle?

Answer 1

R = 9.58 m/s

Step-by-step explanation:

cos(37) = (7.65 m/s)/R

R = (7.65 m/s)/cos(37)

R = 9.58 m/s