Question

Please help me I would really appreciate it.

Answer 1

Given:

`\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}`

To prove:

`\Delta CDA\cong \Delta ABC`

Proof:

In
`\Delta CDA\text{ and } \Delta ABC`,

`\overline{AB}\cong \overline {CD}` because Given

`\overline{BC}\cong \overline {DA}` because Given

`\overline{AC}\cong \overline {AC}` because Reflexive property.

Corresponding sides of both triangles are congruent. So,

`\Delta CDA\cong \Delta ABC` because SSS

Therefore, the required missing values are: Given,
`\overline{BC}\cong \overline {DA}`, Reflexive property ,
`\Delta CDA\cong \Delta ABC`, SSS respectively.