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The molar enthalpy of fusion for water is 6.008 kJ/mol. How much energy is released when 4.81 mol of water freezes?

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Answer: The energy released when 4.81 mol of water freezes is 28.9kJ

Step-by-step explanation:

Latent heat of fusion is the amount of heat required to convert 1 mole of solid to liquid at atmospheric pressure or energy released when 1 mole of liquid freezes to solid at atmospheric pressure.


\Delta H_(fusion) = enthalpy change for fusion = 6.008 KJ/mole

Energy released when 1 mole of water freezes = 6.008 kJ

Energy released when 4.81 moles of water freezes =
(6.008 kJ)/(1)* 4.81mol=28.9kJ

Therefore, the energy released when 4.81 mol of water freezes is 28.9kJ

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