Question

A pool ball moving 1.33 m/s strikes an identical ball at rest. Afterward, the first ball moves 0.814 m/s at a 33.3° angle. What is the x-component and y-component of the velocity of the second ball? pls help quick

Answer 1

the y component is -0.477

Step-by-step explanation:

u1+u2=v1+v2

u1=1.33, u2=0, v1= 0.814sin(33.3)= 0.477, v2=?

so, 1.33+0=0.477+x =

-0.477

Answer 2

X - component = v2 = 0.650 m/s

Y - component = v2 = 0.447 m/s

Step-by-step explanation:

Given that :

Conservation of momentum

m1u1 + m2u2 = m1v1 + m2v2

m = mass of pool ball ; u = initial velocity ; v = final velocity

Since the masses are identical

x - component

u1 + u2 = v1 + v2

u1 = 1.33 m/s

u2 = 0

Final speed of first ball = 0.814 m/s at an angle of 33.3° ;

v1 = 0.814*cos33.3 = 0.814 * 0.8358073 = 0.6803471 m/s

v2x = u1x + u2x - v1

v2x = 1.33 + 0 - 0.6803471

v2x = 0.6496529 m/s

v2x = 0.650 m/s

Y - component :

v1sinθ= 0.814*sin33.3 ; 0.814 * 0.5490228 = 0.4469045 m/s

v2y = 0.447 m/s