Question

in the figure if coefficient of friction between block and surface is 0.2 then find acceleration produced by the resultant force acting on the block (take g= 10 m/s²)​

Answer 1

A N S W E R :

☃ First of all we have to calculate frictional force by using below equation :

→ F = μR

→ F = 0.2 × 5 × 10

→ F = 10 N

• Hence,the frictional force (F) is 10 N.

☃ But we know that frictional force is acting on opposite direction of the motion :

⇏Net force = 15 - 10

⇏Net force = 5 N

• Hence,the net force is 5 N.

☃ By using Newton's second law we get :

• Let the required acceleration produced by the block be 'a'.

➝ Force = mass × acceleration

➝ 5 = 5 × a

➝ a = 5 ÷ 5

➝ a = 1 m/s²

• Hence,the acceleration produced by the resultant force acting on the block is 1 m/s².