Question

What are the xintercepts of the graph of the function below?
y=x^2+4x-32

Answer 1

To find the x intercepts of a given equation, simply substitute in y=0

x^2+4x-32=0


Solve via sum and product (what two numbers add up to +4 and what two numbers multiply to give -32)


x^2+8x-4x-32=0


x(x+8)-4(x+8)=0


(x-4)(x+8)=0

(x-4)=0 and (x+8)=0

So, the two x intercepts are 4 and -8, which is option b

Answer 2

Explanation:

x² + 4x - 32

= (x + 8)(x - 4).

Hence the x-intercepts are (-8, 0) and (4, 0). (B)