Question

The difference of the

ages of two brothers is 4 years 5 years ago if the product of their ages was 96 find their present ages


​

Answer 1

OB - Older Brother

YB - Younger Brother

A) OB -YB = 4

B) OB * YB = 96

B) OB = 96 / YB

Multiplying A) by -1

A) -OB + YB = -4 then we add B)

B) OB = 96 / YB

YB = -4 + 96 / YB

Multiplying both sides by YB

YB^2 = -4YB +96 then re-arranging

YB^2 + 4YB -96 = 0 solving by quadratic equation

AS OF 5 years AGO:

Younger Brother's age = 8

Older Brother's age = 12

NOW THEIR AGES ARE:

8 + 4 = 12 YB and

12 + 4 = 16 OB

Explanation: