Question

Which describes the graph of y=(x+3)^2-4?

Answer 1

(D). Opens up with vertex at (- 3, - 4)

Explanation:

Vertex form of quadratic equation is f(x) = a(x - h)² + k

If a > 0 the parabola is facing up , or down if a < 0 .

(D). Opens up with vertex at (- 3, - 4)

Answer 2

The answer to your question is option d as x is positive ( making it open up), and the vertex is (-3,-4)