Question

What is an equation of the line that passes through the points (-3,1) and

(3, -1)? Put your answer in fully reduced form.

Answer 1

To find the equation of a line, you first have to find the gradient, which is 1--1 / -3-3


So, the gradient is -1/3


Then, substitute one five point into he equation y-y1= m(x-x1) (where m is the gradient)

sub (3,-1)


y+1= -1/3(x-3)


Expand the brackets


y+1= -1/3x+1


Take 1 to the other side as a negative number


So, the line's equation is y=-1/3x

Answer 2

The equation of the line is y = -1/3 x.