Question

A 60N at an angle of 30°from
horizontal​

Answer 1

Step-by-step explanation:

Force, F = 60 N

Angle,
`\theta=30^(\circ)`

We need to find horizontal and vertical component of the force.

Horizontal component,

`F_x=F\cos\theta\\\\=60* \cos(30)\\\\=51.96\ N`

Vertical component,

`F_=F\sin\theta\\\\=60* \sin(30)\\\\=30\ N`

So, the horizontal and vertical component are 51.96 N and 30 N respectively.