Question

Guys help plss:////////​

Answer 1

`f[2-f^(-1)(x)]=x`

Explanation:

Given function is,

f(x) =
`(x-1)/(2)`

Equation form of the function will be,

y =
`(x-1)/(2)`

Interchange x and y,

`x=(y-1)/(2)`

Solve for y,

y = 2x + 1

Therefore, inverse of the function 'f' will be,

`f^(-1)(x)=2x+1`

Now
`[2-f^(-1)(x)]` = 2 - [2x + 1]

= -2x + 1

Value of
`f[2-f^(-1)(x)]` = f(2x + 1)

From the given function,

f(2x + 1) =
`((2x+1)-1)/(2)`

= x

Therefore, value of
`f[2-f^(-1)(x)]=x`