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#1) Line j contains points (-3,5) and (6,-1). If line p is PERPENDICULAR to linej, what is the slope of line p? (Must reduce fraction) * -3/2 3/2 9/4 - 2/3
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#1) Line j contains points (-3,5) and (6,-1). If line p is PERPENDICULAR to linej,

what is the slope of line p? (Must reduce fraction) *
-3/2
3/2
9/4
- 2/3

User Alan Mattano
by
9.5k points

1 Answer

2 votes
First find slope of line j
(-1-5)/(6+3) = -6/9 = -2/3
Perpendicular = opposite sign and reciprocal slope

Solution: 3/2
User Sergey Zakharov
by
8.7k points
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