Question

Someone answer this please...

Answer 1

Hey There!

_____________________________________

Answer:

`\huge\boxed{\text{Magnesium = 120 moles}}`

_____________________________________

Stoichiometry:

The study of relationship between the amounts of reactants and the amount of products in a chemical reaction as given by the balanced chemical equation of the reaction is called the Stoichiometry.

There are three types of stochiometric relationships,

• Mass-Mass Relationship
• Mass-Volume Relationship
• Volume-Volume Relationship

ASSUMPTIONS

To solve the stochiometric questions, we suppose,

• No side reactions takes place.
• Reactants are completely converted into products.

_____________________________________

`\Large\textbf{Methods to Solve}`

There are two methods to solve the stoichiometric problems,

• By mass/volume

• By moles

I prefer the moles method because it is easier to solve and the question is already given in the moles

_____________________________________

`\Huge\textbf{Question:}`

`\Large\textbf{Reaction}`

`3Mg \ +\ 2H_3PO_4\ {\Longrightarrow}\ Mg_3(PO_4)_2_(\downarrow) \ +\ 3H_2_(\uparrow)`

GIVEN DATA

Hydrogen gas = 120 moles

Moles of Magnesium = X = ?

SOLUTION

Since only the value of hydrogen is given and value of magnesium is asked so we will only focus on them only. Thus,

`3Mg\ {\Longrightarrow}\ 3H_2_(\uparrow)`

In the balanced reaction, there are 3 moles of magnesium used and 3 moles of Hydrogen gas are produced, thus The ratio of magnesium and hydrogen is 1 : 1. This means that Whatever amount of magnesium used, the same amount of hydrogen gas will be produced as the magnesium. This was the quick way to guess the answer but if you want to actually solve it here is how,

3 moles of magneisum produce 3 moles of Hydrogen gas

X moles of magnesium produce 120 moles of hydrogen gas

FOR X MOLES:

X =
`(120\ x\ 3)/(3)`

Simplify the equation,

X = 120 moles

_____________________________________

Best Regards,

'Borz'

Answer 2

120 mol Mg

General Formulas and Concepts:

Chemistry - Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

120 moles H₂

Step 2: Identify Conversions

RxN: 3 mol H₂ = 3 mol Mg

Step 3: Stoichiometry

`120 \ mol \ H_2((3 \ mol \ Mg)/(3 \ mol \ H_2) )` = 120 mol Mg