Question

Please answer I need this to get a good grade. (;

Answer 1

94.74 mol NO₂

General Formulas and Concepts:

Chemistry - Stoichiometry

• Using Dimensional Analysis
• STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

Step-by-step explanation:

Step 1: Define

3714 L O₂ at STP

Step 2: Identify Conversions

RxN: 7 mol O₂ = 4 mol NO₂

STP: 22.4 L = 1 mol

Step 3: Stoichiometry

`3714 \ L \ O_2((1 \ mol \ O_2)/(22.4 \ L \ O_2) )((4 \ mol \ NO_2)/(7 \ mol \ O_2) )` = 94.7449 mol NO₂

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

94.7449 mol NO₂ ≈ 94.74 mol NO₂