Question

Sum of the series:
13, 16, 19, ..., 301
how many numbers are in this series?

Answer 1

92

Explanation:

Answer 2

97

Explanation:

13,16,19,...,301

a=13

d=16-13=3

l=a+(n-1)d

301=13+(n-1)3

301-13=(n-1)3

(n-1)3=288

n-1=288/3=96

n=96+1=97