1 Answer

Manmohan Pal · Answer 1 · 2021-02-22T14:53:53+0000

Proof:

In
$\triangle MNP$ and
$\triangle OPN$ :

MN = OP (given)

MP = ON (given)

(common)

$\therefore \triangle MNP \cong \triangle OPN$ (SSS)

$\therefore$
$\angle M \cong \angle O$ since they are corresponding angles of congruent triangles.

Hope this helps :)

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