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Which shows the equation below written in the form ax^2+bx+c=0 ? x^2+8x+10=3

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Answer:


\boxed {\boxed {\sf x^2+8x+7=0}}

Explanation:

We want to put the equation into the standard form of a quadratic equation (
ax^2+bx+c=0). This allows us to factor or use the quadratic formula to find the roots.

We are given the equation:


x^2+8x+10=3

We have to get a 0 on one side of the equation. The easiest way to do this is to "get rid" of the 3 on the right side using inverse operations.

It's a positive 3, so the inverse would be subtract. Subtract 3 from both sides of the equation.


x^2+8x+10-3=3-3


x^2+8x+(10-3)=0


x^2+8x+7=0

The equation in standard form is x²+8x+7=0

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