Question

A. 207 kJ
B. 4730 kJ
C. 9460 kJ
D. 414 kJ

Answer 1

`\boxed {\boxed {\sf C. \ 9460 \ kJ}}`

Step-by-step explanation:

The formula we must use is given to us:

`q=mL_(vapor)`

q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.

The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.

• We know the sample is copper.
• Find that element on the table, then the third box tells us it's latent heat of vaporization is 4730 kJ/kg

Now we know:

`m= 2 \ kg \\L_(vapor)=4730 \ kJ/kg`

Substitute the values into the formula.

`q=(2 \ kg ) * (4730 \ kJ/kg)`

Multiply. Note that the kilograms (kg) will cancel each other out.

`q= 2* 4730 \ kJ`

`q= 9460 \ kJ`

9460 kilojoules are required to vaporize 2 kilograms of copper.