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A. 207 kJ
B. 4730 kJ
C. 9460 kJ
D. 414 kJ

A. 207 kJ B. 4730 kJ C. 9460 kJ D. 414 kJ-example-1

1 Answer

5 votes

Answer:

Q = 9460 Kj

Step-by-step explanation:

Given data:

Mass of copper = 2kg

Latent heat of vaporization = 4730 Kj/Kg

Energy required to vaporize 2kg copper = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram copper is 4730 Kj thus, for 2 kg

by putting values,

Q= 2kg × 4730 Kj/Kg

Q = 9460 Kj

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