Given :
The mass of the balloon was 1890 kg and had a volume of 11,430 m3 .
The balloon floats at a constant height of 6.25m above the ground.
To Find :
The density of the hot air in the balloon.
Solution :
We know,
Volume × ( Density of surrounding air - Density of hot air ) = mass
Putting given values in above equation, we get :
![11430* ( 1.29 - \rho_(hot \ air ) ) = 1890\\\\\rho_(hot \ air ) = 1.29 - (1890)/(11430)\\\\\rho_(hot \ air ) = 1.125\ kg\ m^3](https://img.qammunity.org/2021/formulas/physics/college/5ptl7ugbah5e00fxu94hsc0p36ys25vd8d.png)
Therefore, the density of hot air in the balloon is 1.125 kg m³.