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g Estimate the number of photons emitted by the Sun in a second. The power output from the Sun is 4 × 1026 W and assume that the average wavelength of each photon is 550 nm.

User Ben Flynn
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Answer:

The value is
N = 1.107 *10^(45 ) \ photons

Step-by-step explanation:

From the question we are told that

The power output from the sun is
P_o = 4 * 10^(26) \ W

The average wavelength of each photon is
\lambda = 550 \ nm = 550 *10^(-9) \ m

Generally the energy of each photon emitted is mathematically represented as


E_c = (h * c )/( \lambda )

Here h is the Plank's constant with value
h = 6.62607015 * 10^(-34) J \cdot s

c is the speed of light with value
c = 3.0 *10^(8) \ m/s

So


E_c = (6.62607015 * 10^(-34) * 3.0 *10^(8) )/( 550 *10^(-9) )

=>
E_c = 3.614 *10^(-19) \ J

Generally the number of photons emitted by the Sun in a second is mathematically represented as


N = (P )/(E_c)

=>
N = (4 * 10^(26) )/(3.614 *10^(-19))

=>
N = 1.107 *10^(45 ) \ photons

User Edmundpie
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