Question

Two ships leave the port at 12 noon. Ship A is traveling at the bearing of 146 at 20 miles per hour, and ship B travels at a bearing of N32 E at 28 miles per hour. Approximate how far apart ships are at 3 PM. At what bearing ship A is from ship B at 3 PM.

Answer 1

Answer:
`d = 103.23 miles` apart.

Explanation:

given data:

ship a = 20miles. = 60miles

ship b = 28miles. = 84miles

time interval = 3hrs.

θ = 90

`d = \sqrt{a^(2)+b^(2)-2ab (cos90) }`

`d = \sqrt{60^(2)+84^(2)-2(60)(84) *(cos90) }`

`d = √(3600+7056-10080*(cos90) )`

`d = √(10656-10080*(cos90) )`

`d = \sqrt{10656-0`

`d = \sqrt{10656`

`d = 103.23 miles`