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Somebody Please solve this question without using L Hospital rule.

Evaluate if:​

Somebody Please solve this question without using L Hospital rule. Evaluate if:​-example-1
User Xantham
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1 Answer

6 votes

Answer:

1/2

Explanation:

Given that,


\lim_(n \to 1) ((1+\cos\pi x)/(\tan^2\pi x))

Using L Hospital's rule to find it :


\lim_(n \to a) (f(x))/(g(x))= \lim_(n \to a) (f'(x))/(g'(x))

We have,

a = 1,
f(x)=1+\cos\pi x, \ \ g(x)=\tan^2\pi x


f'(x)=(d)/(dx)(1+\cos\pi x)\\\\=-\pi \sin \pi x\ .....(1)


g'(x)=(d)/(dx)(\tan^2\pi x)\\\\=2\tan\pi x* \sec^2\pi x* \pi\ .....(2)

From equation (1) and (2) :


\lim_(n \to 1) (f(x))/(g(x))= \lim_(n \to 1) (-\pi \sin\pi x)/(2\tan \pi x* \sec^2\pi x * \pi)\\\\\lim_(n \to 1) (-\pi \sin\pi x)/(2\tan \pi x* \sec^2\pi x * \pi)\\\\=\lim_(n \to 1) (-1)/(2)*\cos^3\pi x\\\\=(-1)/(2)* \cos^3\pi \\\\=(1)/(2)

So, the value of the given function is 1/2.

User Benselme
by
8.3k points

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