Question

When a 54.9-g tennis ball is served, it accelerates from rest to a speed of 45.1 m/s. The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm. What is the magnitude of the net force acting on the ball

Answer 1

F = 159.07 N

Step-by-step explanation:

Given that,

Mass of a tennis ball, m = 54.9 g = 0.0549 kg

It accelerates from rest to a speed of 45.1 m/s.

The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm = 0.351 m

We need to find the magnitude of net force acting on the ball.

Let a be the acceleration of the ball. Using third equation of motion to find it.

`v^2-u^2=2ad\\\\a=(v^2-u^2)/(2d)\\\\a=((45.1)^2-(0)^2)/(2* 0.351)\\\\=2897.45\ m/s^2`

Net force,

F = ma

F = 0.0549 kg × 2897.45 m/s²

= 159.07 N

Hence, the net force acting on the ball is 159.07 N.