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A man stands on top of a cliff and shouts.

He hears the echo on the third clap when
he claps his hand at the rate of two claps
per second. What is the distance between
man & the obstruction, if the velocity of
sound is 320 m/s

1 Answer

2 votes


\small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x


\small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = (2x)/(v) = 1


\bf \to \: x = (320)/(2) m = 160m


\small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m * 2 = 320m

User Will Madden
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