Question

A 150-turn coil of wire moves perpendicularly through a uniform magnetic field in 1.1 s. If the field increases uniformly from 0.00 T to 0.95 T and each coil of wire has an area of 1.4 m2, use Faraday’s law of magnetic induction to find the magnitude of the induced emf in the coil:

a. 180 V
b. 1800 V
c. -180 V
d. -18 V

Answer 1

Hope this helps.......☺

Answer 2

-180 V

Step-by-step explanation:

Given that,

No. of turns, N = 150

If the field increases uniformly from 0.00 T to 0.95 T and each coil of wire has an area of 1.4 m²

The coil will move perpendicular through a uniform magnetic field in 1.1 s.

We need to find the magnitude of the induced emf in the coil. The formula for the induced emf is given by :

`\epsilon=(-d\phi)/(dt)\\\\=(-d(BA))/(dt)\\\\=-A(dB)/(dt)`

Put all the values,

`\epsilon=-NA(dB)/(dt)\\\\=-150* 1.4* (0.95-0)/(1.1)\\\\=-181.36\ V`

Out of four options, induced emf is (-180 V)

So, induced emf in the coil is (-180 V). Hence, the correct option is (c).