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A 150-turn coil of wire moves perpendicularly through a uniform magnetic field in 1.1 s. If the field increases uniformly from 0.00 T to 0.95 T and each coil of wire has an area of 1.4 m2, use Faraday’s law of magnetic induction to find the magnitude of the induced emf in the coil:

a. 180 V
b. 1800 V
c. -180 V
d. -18 V

2 Answers

7 votes

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A 150-turn coil of wire moves perpendicularly through a uniform magnetic field in-example-1
User Niklasae
by
8.9k points
7 votes

Answer:

-180 V

Step-by-step explanation:

Given that,

No. of turns, N = 150

If the field increases uniformly from 0.00 T to 0.95 T and each coil of wire has an area of 1.4 m²

The coil will move perpendicular through a uniform magnetic field in 1.1 s.

We need to find the magnitude of the induced emf in the coil. The formula for the induced emf is given by :


\epsilon=(-d\phi)/(dt)\\\\=(-d(BA))/(dt)\\\\=-A(dB)/(dt)

Put all the values,


\epsilon=-NA(dB)/(dt)\\\\=-150* 1.4* (0.95-0)/(1.1)\\\\=-181.36\ V

Out of four options, induced emf is (-180 V)

So, induced emf in the coil is (-180 V). Hence, the correct option is (c).

User Ray Jezek
by
8.1k points
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