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If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?

1 Answer

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Answer:

m = 0.25

Step-by-step explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.


(1)/(v)+(1)/(u)=(1)/(f)\\\\(1)/(v)=(1)/(f)-(1)/(u)\\\\=(1)/(5)-(1)/((-15))\\\\=3.75\ cm

Magnification,


m=(-v)/(u)\\\\=(-3.75)/(-15)\\\\=0.25

Hence, the magnification of the image is 0.25.

User Dan McGrath
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