a 6.5 kg box is pulled across a floor by a horizontal 12.0 N tension force. If there is a 5 N friction exerted on the box, what is its acceleration

asked Oct 1, 2021 157k views

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Step-by-step explanation:

Fnet = 12.0N - 5.0N = 7.0N

a = Fnet/m = 7.0N/6.5kg = 1.07m/s².

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