Question

For the chemical reaction:

N2 (g)
+
H2(g)=
NH3 (g)
Calculate the volume of NH; that will form from 200 dm cubed of N2 at STP. (N = 14; H - 1)
[At STP. 1 mole of any gas occupies volume of 22 A dm cubed​

Answer 1

Volume of ammonia produced = 398.7 dm³

Step-by-step explanation:

Given data:

Volume of N₂ = 200 dm³

Pressure and temperature = standard

Volume of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of N₂:

PV = nRT

1 atm× 200 L = n× 0.0821 atm.L/mol.K × 273 K

n = 200 atm.L /22.41 atm.L/mol

n = 8.9 mol

Now we will compare the moles of ammonia and nitrogen.

N₂ : NH₃

1 : 2

8.9 : 2/1×8.9 = 17.8 mol

Volume of ammonia:

1 mole of any gas occupy 22.4 dm³ volume

17.8 mol ×22.4 dm³/1 mol = 398.7 dm³