Question

This is a two part question:

What is the magnitude net force acting on an object that is pushed by a 430N and experiences 120N force?
430N
120N
310N
550N

If a net force of 375N is acting on a crate and there is 65N of friction
created, what is the magnitude net force the crate experiences?
375N
65N
310N
440N

Answer 1

1. 310 N

2. 310 N

Step-by-step explanation:

1. Determination of the net force.

Force applied (Fₐ) = 430 N

Force experience (Fₑ) = 120 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fₑ

Fₙ = 430 – 120

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N

2. Determination of the net force.

Force applied (Fₐ) = 375 N

Force of friction (Fբ) = 65 N

Net force (Fₙ) =?

Fₙ = Fₐ – Fբ

Fₙ = 375 – 65

Fₙ = 310 N

Hence, the net force acting on the crate is 310 N.