Question

If a net force of 375N is acting on a crate and there is 65N of friction

created, what is the magnitude net force the crate experiences?
375N
65N
310N
440N

Answer 1

310 N

Step-by-step explanation:

The net force, I assume, is an applied force that is causing motion of the crate. However, frictional force opposes this motion, so the frictional force is in the opposite direction. Overall, we can create a net force equation of this crate as

Fnet= Force applied + Force of friction

Thus,

Fnet= 375N -65N (because friction is in the opposite direction)

Then solve to get that the net force while the crate is in motion is 310N.