Given:
The function is
![f(x)=(x+3)^2(x-5)^6](https://img.qammunity.org/2021/formulas/mathematics/high-school/fxyu9jho6f1aovvlytqbpn7k98jkmy0zdx.png)
To find:
The zeros of the given function.
Solution:
The general form of polynomial is
...(i)
where, a is a constant,
are zeros of respective multiplicities
.
We have,
![f(x)=(x+3)^2(x-5)^6](https://img.qammunity.org/2021/formulas/mathematics/high-school/fxyu9jho6f1aovvlytqbpn7k98jkmy0zdx.png)
On comparing this with (i), we get
![c_1=-3,m_1=2](https://img.qammunity.org/2021/formulas/mathematics/high-school/2f4hr7lln5hy49n0wibu79enb7kihaui76.png)
![c_2=5,m_2=6](https://img.qammunity.org/2021/formulas/mathematics/high-school/vz9wcr09ntyttu66fd4took6b6mt3qo6zx.png)
It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.
Therefore, the correct option is B.