Question

a, b, and c represent three different digits. If you add up all of the six two - digit numbers that can be written with these digits, where you don't use the same digit twice in each number, then the sum will be 528. Find these digits.

Answer 1

The answer is 7, 8 and 9. The Two-digit numbers are: ab, ac, ba, bc, ca, cb

The Sum of them is: 10a + b + 10a + c + 10b + a + 10b + c + 10c + a + 10c + b = 528

22a + 22b + 22c = 528

a + b + c = 528/22

a + b + c = 24 The only option/options of the three different digits with the sum of 24 is 7, 8 and 9.

Hope this helps, stay safe, and merry christmas!

Answer 2

• 7, 8 and 9

Explanation:

Two-digit numbers are:

• ab, ac, ba, bc, ca, cb

Sum of them is:

• 10a + b + 10a + c + 10b + a + 10b + c + 10c + a + 10c + b = 528
• 22a + 22b + 22c = 528
• a + b + c = 528/22
• a + b + c = 24

The only option of three different digits with the sum of 24 is 7, 8 and 9