Question

The specific heat of iron is 0.46 J/g°C. How many joules will it take to make the temperature of a 150. g bar go up from 25°C to 60.°C?

Answer 1

Q = 2.415kj

Step-by-step explanation:

Q = Mc∆temperature

c = 0.46j/g°c = 0.46kj/kg°c

mass = 150g = 0.15kg

∆temperature = 60 - 25 = 35°c

Q = 0.15 X 0.46 X 35 = 2.415kj

Q = 2.415kj