Question

Find the 10th term of the geometric sequence show below

3x^7,9x^9, 27x^11...

PLEASE ANSWER!! TY

Answer 1

t_10 = 59049 x^25

Explanation:

a = 3x^7

r = 3 x^2

t_10 = (3x^7)(3x^2)^10

t_10 = 3x^7 3^(10-1) * (x^2)^(10 - 1)

t_10 = 3x^7 * 3^9 * (x^2)^9

t_10 = 3x^7 * 19683 x^18

t_10 = 59049 x^25