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In circle M, diameters JL and HK each measure 16 centimeters. What is the approximate length of minor arc JH? Round to the nearest tenth of a centimeter. 3.5 cm 6.9 cm 21.6 cm 46.8 cm

User Proxpero
by
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2 Answers

2 votes

Answer:

A. 3.5 cm

Explanation:

In the picture attached, circle M is shown.

From the picture, minor arc JH measures 25°.

The length of the circle is π*Diameter = π*16 = 50.26 cm. This length is proportional to 360°. To find the length of minor arc JH, we have to use the next proportion:

50.26 cm / x cm = 360° / 25°

x = 50.26*25/360

x = 3.5 cm

User Jkinkead
by
4.4k points
1 vote

Answer:

3.5 cm

Explanation:

The computation of the approximate length of minor arc JH is as follows

As in the attached picture we can see that circle M is shown also the minor arc measures 25 degrees

Now the circle length is

= π × 16

= 50.26 cm.

Now this length would be proportional to 360 degrees

Let us assume the minor length arc JH be x

So, the equation would be

50.26 cm ÷ x cm = 360° ÷ 25°

x = 50.26 × 25 ÷ 360

x = 3.5 cm

In circle M, diameters JL and HK each measure 16 centimeters. What is the approximate-example-1
User Bpgergo
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