Let the daily rate of each associate, A = $700
And the daily rate of each partner, P = $1700
Let the total number of individuals involved in the case = NT
Total number of partners = NP
Total number of associates = NA
NP + NA = NT -------- (i)
From the question; NP - NA = 4 -------- (ii)
From (i), NA = NT - NP
Substitute in (ii) as: NP - (NT - NP) = 4
Therefore, 2NP - NT = 4.
And NP = 2 + (NT/2) --------- (iii)
Substitute for NP in (i) above: NT = NA + 2 + (NT/2)
Therefore, NT - (NT/2) - 2 = NA.
NA = (NT/2) - 2 ---------- (iv)
Finally, the total daily rate was $21200. This is a composite of the daily rate and numbers of both associates and partners.
Therefore, (A * NA) + (P * NP) = $21200 ---------- (v)
To find the individual number of associates and partners involved in this case, first substitute the values of NP and NA from (iii) and (iv) respectively into (v) such that the only variable in (v) is NT.
Solve for NT and then use the value to find NP and NA.
NT = 16
NP = 10
NA = 6
Notice that 10 - 6 = 4. Q.E.D
Hope this helps.