Question

Y^3-8y^2+19y=12
Solve​

Answer 1

Explanation:

steps are below

step 1

y^3-8y^2+19y=12 equation

step 2

y^3-8y2+19y(-12)=12(-12) minus 12 from both sides

y^3-8y^2+19y-12=0

step 3

(y-1)(y-3)(y-4)=0 add brackets

step 4

(y-1)(y-3)(y-4)=0 factor

step 5

y-1=0 or y−3=0 or y-4=0 set them equal

Answer:

y=1 or y=3 or y=4