Question

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1. If you were to combine hydrogen with 80.0 g of oxygen, how much hydrogen would
you need to completely react with all of the oxygen?

2. Suppose sodium and chlorine form a compound in the ratio of 1.54 g chlorine to
1.0 g sodium. How much sodium would be needed to completely react with 45.0
of chlorine?

Answer 1

Mass of hydrogen needed = 10 g

29.22 gram of sodium are required

Step-by-step explanation:

1 )Given data:

Mass of oxygen = 80.0 g

Mass of hydrogen needed = ?

Solution:

Chemical equation:

2H₂ + O₂ → 2H₂O

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 80 g/ 32 g/mol

Number of moles = 2.5 mol

now we will compare the moles of oxygen and hydrogen.

O₂ : H₂

1 : 2

2.5 : 2× 2.5 = 5 mol

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 5 mol × 2 g/mol

Mass = 10 g

2 : Given data:

initial mass ration of chlorine and sodium react with each other = 1.54 g : 1.0 g

Mass of sodium required for 45 g of chlorine = ?

Solution:

Cl₂ : Na

1.54 : 1.0

45 : 1.0/1.54× 45 = 29.22 g

Thus, 29.22 gram of sodium are required.