Question

Helppppppppppppppppppppppppp

Answer 1

Option A

Explanation:

We know that for an eqn.
`ax^(2) +bx+c=0` , the quadratic formula is =

`x = \frac{-b+\sqrt{b^(2)-4ac } }{2a} or \frac{-b-\sqrt{b^(2)-4ac } }{2a}`

So using quadratic eqn. for
`x^(2) -6x-5=0`

`x =\frac{-(-6)+\sqrt{(-6)^(2)-4*1*(-5) } }{2*1}or\frac{-(-6)-\sqrt{(-6)^(2)-4*1*(-5) } }{2*1}`

`=> x = (6+√(36+20) )/(2) or(6-√(36+20) )/(2)`

`=>x = (6+√(56) )/(2) or(6-√(56) )/(2)`