Question

Quadrilateral ABCD is translated to get quadrilateral A'B'C'D'. vertex A is at (-5,2) , and vertex A' is ay (2,-2), quadrilateral ABCD is translated blank..... if vertex B is at (-6,5), then vertex B is at​

Answer 1

(-1,3)

Explanation:

Given that the quadrilateral ABCD is translated to get quadrilateral A'B'C'D'. The vertex A is at (-5,2) is translated to vertex A' is at (2,-2).

The translation is x-direction, a, is the difference of x-coordinates of both the points, a=2-(-5)=2+5=7.

The translation is y-direction, b, is the difference of y-coordinates of both the points, b = -2-2 = -4.

As all the points are translated by the same magnitude as well as in the same direction, so by adding a to x and b to y coordinate of any points, the translated point can be determined.

The vertex of point B is (-6,5), so, the vertex of the point B' would be (-6+a, 5+b)=(-6+7, 5+(-4))=(-1,3).

Hence, the vertex of point B' is (-1,3).