Question

From first principle find the derivative of logx​

Answer 1

Hello!

`\large\boxed{(dy)/(dx)logx = (1)/(xln10) }`

Recall that:

`logx` can be rewritten as:

`log_(10)x`

Use the equation for the derivative of a log expression:

`(dy)/(dx)log_(a)u = (1)/(ulna) * u'`

Substitute in the values in the expression:

`logx = (1)/(xln10) * 1 = (1)/(xln10)`