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If a line crosses the y-axis at (0, 1) and has a slope of 4/5 , what is the equation of the line? ОА. 4y-5x=5 OB. y- 4x = 5 O C. 5y + 4x = 5 OD. 5y - 4x = 5 I need help

If a line crosses the y-axis at (0, 1) and has a slope of 4/5 , what is the equation of the line? ОА. 4y-5x=5 OB. y- 4x = 5 O C. 5y + 4x = 5 OD. 5y - 4x = 5 I need help
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If a line crosses the y-axis at (0, 1) and has a slope of 4/5 , what is the equation of the line?

ОА.
4y-5x=5
OB.
y- 4x = 5
O C.
5y + 4x = 5
OD. 5y - 4x = 5
I need help

User Simonzack
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1 Answer

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