Question

For a moving object, the force acting on the object where is directly from the objects acceleration. When a force of 21 N Acts on a certain object, the acceleration of the object is 7 m/s^2. If the acceleration of the object becomes 9 m/s^2, what is the force?

Answer 1

`F = 27N`

Explanation:

Given

Force directly proportional to acceleration

Force = 21N when Acceleraion = 7m/s^2

Required

Determine the force when acceleration = 9m/s^2

The variation between force (F) and acceleration (A) implies that:

`F\ \alpha\ \ A`

Convert to an equation

`F = mA`

Where m is constant.

When F = 21 and A = 7, we have:

`21 = m * 7`

Solve for m

`m = (21)/(7)`

`m = 3`

When A = 9

Substitute 9 for A and 3 for m in
`F = mA`

`F = 3 * 9`

`F = 27N`