Question

HELP NOW PLS !!

If you exert 950 N*s of impulse on a 12 kg frictionless cart over the course of 5 seconds, how far will it travel during those seconds?

Answer 1

The value is
`s =197.88 \ m`

Step-by-step explanation:

From the question we are told that

The impulse is
`I = 950 \ N\cdot s`

The mass is
`m = 12 \ kg`

The time t = 5 s

Generally impulse is mathematically represented as

`I = F * t`

=>
`F = (I)/(t)`

=>
`F = (950 )/( 5 )`

=>
`F = 190 \ N`

Generally force is mathematically represented as

`F = m * a`

=>
`a = (F )/( m )`

=>
`a = (190 )/( 12 )`

=>
`a = 15.83 \ m/s^2`

Generally from kinematic equation , the distance covered is

`s = ut + (1)/(2) * at^2`

Here u is the initial velocity of the cart and the value is
`u = m/s`

=>
`s = 0 * 5 + (1)/(2) * 15.83 * 5^2`

=>
`s =197.88 \ m`