Answer:
Khalid’s rate is 140 mi/h. Jesse’s rate is 150 miles per hour
So, Jesse’s train traveled at a faster speed
Explanation:
Here, we want to compare speeds
For Jesse’s train, the speed is 150 mi/h
we got this from the fact that the equation of a straight line is represented as;
y = mx + b
where m which is the slope represents the rate of change
m here is 150
For Khalid’s;
we can get his own rate from the graph
This can be obtained using the slope
We can simply have this as ;
m = (y2-y1)/(x2-x1)
Let us have two points
(4,560) and (0,0)
Thus;
m = 560/4 = 140 mi/h
Hence;
Khalid’s rate is 140 mi/h. Jesse’s rate is 150 miles per hour
So, Jesse’s train traveled at a faster speed