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In tomatoes, the following hypothetical pathway gives rise to different fruit colors. Y gene R gene Precursor substrate Intermediate substrate Product and lacks color and fruit is and fruit is yellow fruit is red green from chlorophyll Mutations in the genes for both of the enzymes produce lack-of-function, recessive alleles. What would be the expected genotypic and phenotypic segregation ratios if you self-fertilize a RrYy individual

User Chrischu
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Answer:

Step-by-step explanation:

From the information given:

The analysis of the hypothetical pathway gives:

Y gene R gene

Green fruit → Yellow fruit → Red fruit.

If RrYy undergoes self-fertilization, the expected genotypic and phenotypic segregation is:

RrYy × RrYy

The progenitors to undergo the segregation are as follows:

RY Ry rY ry

RY RRYY RRYy RrYY RrYy

(red) (red) (red) (red)

Ry RRYy RRyy RrYy Rryy

(red) (green) (red) (green)

rY RrYY RrYy rrYY rrYy

(red) (red) (yellow) (yellow)

ry RrYy Rryy rrYy rryy

(red) (green) (yellow) (green)

Thus; the expected phenotypic ratio is:

= 9(red) : 3(yellow) : 4(green)

The expected phenotypic ratio is:

= 1(RRYY): 2(RRYy): 2(RrYY): 4(RrYy): 1(RRyy): 2(Rryy): 1(rrYY): 2(rrYy): 1(rryy)

User Teddy Engel
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