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Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​

1 Answer

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Avogadro's law states that in a mole of any substance, there are
6.022 * 10^(23) atoms. This means that in the given sample, there are


(6.075 * 10^(26))/(6.022 * 10^(23))=1008.8010627 \text{ mol}

  • The atomic mass of sulfur is 32.06 amu.
  • The atomic mass of oxygen is 15.9994 amu.

So, the atomic mass of sulfur dioxide is


32.06+2(15.9994=64.0588 \text{ g/mol}

Therefore, the mass is:


(64.0588)(1008.8010627)=\boxed{64620 \text{ g (to 4 sf)}}

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