Answer:
The slope of the line passing through the points (−3, −5) and (−1, −6) is
(-0.5)
Explanation:
Equation of a straight line:
y = mx + b where m is the slope and b is the y-intercept
(x1, x2) and (y1, y2) : (−3, −5) and (−1, −6)
Calculating Slope (m).
m =
![(y_(2) - y_(1))/(x_(2) - x_(1))](https://img.qammunity.org/2023/formulas/mathematics/college/dthlwonushe9o6fl6hflq2mc54ztdj94nw.png)
m =
![( (-6) - (-5) )/( (-1) - (-3) )](https://img.qammunity.org/2023/formulas/mathematics/college/pz7fh34wxr4q6k2mc4p61y4n98nisomkte.png)
m =
![( -6 + 5 )/( -1 + 3 )](https://img.qammunity.org/2023/formulas/mathematics/college/wibutbmfeios8itkf9buexrki4aaifabwk.png)
m =
![-( 1 )/( 2 )](https://img.qammunity.org/2023/formulas/mathematics/college/erb8p2xvm9xhkkdzch0viukmyhjmno4muu.png)
we can take this a step further by finding the equation:
Now putting value of m in equation (i)
y = -0.5x + b
Calculating Y-intercept (b).
Lets choose the first point, (-3,-5) for calculating y-intercept:
y = mx + b
-5 = -0.5(-3) + b
-5 = 1.5 + b
-6.5 = b
b = -6.5
Now putting value of b in equation
y = -0.5x + -6.5