Question

Can I have an answer for this?

Answer 1

Hey There!

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Answer:

`\huge\boxed{\text{11.25 grams/mols}}`

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Reaction:

`2Al_((s))+ 3FeO_((s)) \overset{\Delta} {\Longrightarrow} 3Fe_((s))+Al_2O_3_((s))`

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DATA:

Mass of Aluminium: 27
`(gm)/(mol)`

Mass of Ferous Oxide: 71.84
`(gm)/(mol)`

Aluminium: 7.5 Moles Given

How many moles of Iron (II) oxide(FeO)?

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SOLUTION:

As there are 2 moles of aluminium involved and 3 moles of ferrous oxide So,

2 moles Al and 3 moles FeO

7.5 moles Al and x moles FeO

For X moles:

X =
`(3\ x\ 7.5 )/(2)`

X=
`(22.5)/(2)`

X= 11.25
`(gm)/(mol)`

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Best Regards,

'Borz'